Howard had 60 more coins than Ben. Howard gave 25% of his coins to Ben. Ben in return gave 60% of his coins to Howard. In the end, Ben had 168 less coins than Howard. How many coins did Howard have at first?
| |
Howard |
Ben |
Comparing Howard
and Peter at first |
60 more |
|
| Before |
4 u + 60 |
4 u |
| Change 1 |
- 1 u - 15 |
+ 1 u + 15 |
| After 1 |
3 u + 45 |
5 u + 15 |
| Change 2 |
+ 3 u + 9 |
- 3 u - 9 |
| After 2 |
6 u + 54 |
2 u + 6 |
25% =
25100 =
1425% x 60
=
25100 x 60
= 15
60% x 15
=
60100 x 15
= 9
60% x 5 u
=
60100 x 5 u
= 3 u
Ben had 168 less coins than Howard in the end. If another 168 coins are given to Ben, both will have the same number of coins.
6 u + 54 = 2 u + 6 + 168
6 u - 2 u = 6 + 168 - 54
4 u = 120
1 u = 120 ÷ 4 = 30
Number of Ben's coins at first
= 4 u
= 4 x 30
= 120
Answer: 120
