Paul had 120 more stamps than Perry. Paul gave 20% of his stamps to Perry. Perry in return gave 50% of his stamps to Paul. In the end, Paul had 276 more stamps than Perry. How many stamps did Paul have at first?
| |
Paul |
Perry |
Comparing Paul
and Peter at first |
120 more |
|
| Before |
5 u + 120 |
5 u |
| Change 1 |
- 1 u - 24 |
+ 1 u + 24 |
| After 1 |
4 u + 96 |
6 u + 24 |
| Change 2 |
+ 3 u + 12 |
- 3 u - 12 |
| After 2 |
7 u + 108 |
3 u + 12 |
20% =
20100 =
1520% x 120
=
20100 x 120
= 24
50% x 24
=
50100 x 24
= 12
50% x 6 u
=
50100 x 6 u
= 3 u
Paul had 276 more stamps than Perry in the end. If another 276 stamps are given to Perry, both will have the same number of stamps.
7 u + 108 = 3 u + 12 + 276
7 u - 3 u = 12 + 276 - 108
9 u = 180
1 u = 180 ÷ 9 = 20
Number of Paul's stamps at first
= 5 u + 120
= 5 x 20 + 120
= 100 + 120
= 220
Answer: 220
