Pierre had 110 more beads than Julian. Pierre gave 20% of his beads to Julian. Julian in return gave 50% of his beads to Pierre. In the end, Pierre had 392 more beads than Julian. How many beads did Pierre have at first?
| |
Pierre |
Julian |
Comparing Pierre
and Peter at first |
110 more |
|
| Before |
5 u + 110 |
5 u |
| Change 1 |
- 1 u - 22 |
+ 1 u + 22 |
| After 1 |
4 u + 88 |
6 u + 22 |
| Change 2 |
+ 3 u + 11 |
- 3 u - 11 |
| After 2 |
7 u + 99 |
3 u + 11 |
20% =
20100 =
1520% x 110
=
20100 x 110
= 22
50% x 22
=
50100 x 22
= 11
50% x 6 u
=
50100 x 6 u
= 3 u
Pierre had 392 more beads than Julian in the end. If another 392 beads are given to Julian, both will have the same number of beads.
7 u + 99 = 3 u + 11 + 392
7 u - 3 u = 11 + 392 - 99
8 u = 304
1 u = 304 ÷ 8 = 38
Number of Pierre's beads at first
= 5 u + 110
= 5 x 38 + 110
= 190 + 110
= 300
Answer: 300
