Seth had 70 more buttons than Perry. Seth gave 20% of his buttons to Perry. Perry in return gave 50% of his buttons to Seth. In the end, Seth had 212 more buttons than Perry. How many buttons did Seth have at first?
| |
Seth |
Perry |
Comparing Seth
and Peter at first |
70 more |
|
| Before |
5 u + 70 |
5 u |
| Change 1 |
- 1 u - 14 |
+ 1 u + 14 |
| After 1 |
4 u + 56 |
6 u + 14 |
| Change 2 |
+ 3 u + 7 |
- 3 u - 7 |
| After 2 |
7 u + 63 |
3 u + 7 |
20% =
20100 =
1520% x 70
=
20100 x 70
= 14
50% x 14
=
50100 x 14
= 7
50% x 6 u
=
50100 x 6 u
= 3 u
Seth had 212 more buttons than Perry in the end. If another 212 buttons are given to Perry, both will have the same number of buttons.
7 u + 63 = 3 u + 7 + 212
7 u - 3 u = 7 + 212 - 63
4 u = 156
1 u = 156 ÷ 4 = 39
Number of Seth's buttons at first
= 5 u + 70
= 5 x 39 + 70
= 195 + 70
= 265
Answer: 265
