Cole had 200 more buttons than Pierre. Cole gave 25% of his buttons to Pierre. Pierre in return gave 80% of his buttons to Cole. In the end, Cole had 360 more buttons than Pierre. How many buttons did Cole have at first?
| |
Cole |
Pierre |
Comparing Cole
and Peter at first |
200 more |
|
| Before |
4 u + 200 |
4 u |
| Change 1 |
- 1 u - 50 |
+ 1 u + 50 |
| After 1 |
3 u + 150 |
5 u + 50 |
| Change 2 |
+ 4 u + 40 |
- 4 u - 40 |
| After 2 |
7 u + 190 |
1 u + 10 |
25% =
25100 =
1425% x 200
=
25100 x 200
= 50
80% x 50
=
80100 x 50
= 40
80% x 5 u
=
80100 x 5 u
= 4 u
Cole had 360 more buttons than Pierre in the end. If another 360 buttons are given to Pierre, both will have the same number of buttons.
7 u + 190 = 1 u + 10 + 360
7 u - 1 u = 10 + 360 - 190
9 u = 180
1 u = 180 ÷ 9 = 20
Number of Cole's buttons at first
= 4 u + 200
= 4 x 20 + 200
= 80 + 200
= 280
Answer: 280
