Vincent had 110 more pens than Xavier. Vincent gave 20% of his pens to Xavier. Xavier in return gave 50% of his pens to Vincent. In the end, Xavier had 264 less pens than Vincent. How many pens did Vincent have at first?
| |
Vincent |
Xavier |
Comparing Vincent
and Peter at first |
110 more |
|
| Before |
5 u + 110 |
5 u |
| Change 1 |
- 1 u - 22 |
+ 1 u + 22 |
| After 1 |
4 u + 88 |
6 u + 22 |
| Change 2 |
+ 3 u + 11 |
- 3 u - 11 |
| After 2 |
7 u + 99 |
3 u + 11 |
20% =
20100 =
1520% x 110
=
20100 x 110
= 22
50% x 22
=
50100 x 22
= 11
50% x 6 u
=
50100 x 6 u
= 3 u
Xavier had 264 less pens than Vincent in the end. If another 264 pens are given to Xavier, both will have the same number of pens.
7 u + 99 = 3 u + 11 + 264
7 u - 3 u = 11 + 264 - 99
4 u = 176
1 u = 176 ÷ 4 = 22
Number of Xavier's pens at first
= 5 u
= 5 x 22
= 110
Answer: 110
