Tommy had 80 more stickers than Sean. Tommy gave 25% of his stickers to Sean. Sean in return gave 80% of his stickers to Tommy. In the end, Tommy had 132 more stickers than Sean. How many stickers did Tommy have at first?
| |
Tommy |
Sean |
Comparing Tommy
and Peter at first |
80 more |
|
| Before |
4 u + 80 |
4 u |
| Change 1 |
- 1 u - 20 |
+ 1 u + 20 |
| After 1 |
3 u + 60 |
5 u + 20 |
| Change 2 |
+ 4 u + 16 |
- 4 u - 16 |
| After 2 |
7 u + 76 |
1 u + 4 |
25% =
25100 =
1425% x 80
=
25100 x 80
= 20
80% x 20
=
80100 x 20
= 16
80% x 5 u
=
80100 x 5 u
= 4 u
Tommy had 132 more stickers than Sean in the end. If another 132 stickers are given to Sean, both will have the same number of stickers.
7 u + 76 = 1 u + 4 + 132
7 u - 1 u = 4 + 132 - 76
3 u = 60
1 u = 60 ÷ 3 = 20
Number of Tommy's stickers at first
= 4 u + 80
= 4 x 20 + 80
= 80 + 80
= 160
Answer: 160
