Ahmad had 150 more coins than Ivan. Ahmad gave 20% of his coins to Ivan. Ivan in return gave 50% of his coins to Ahmad. In the end, Ivan had 360 less coins than Ahmad. How many coins did Ahmad have at first?
| |
Ahmad |
Ivan |
Comparing Ahmad
and Peter at first |
150 more |
|
| Before |
5 u + 150 |
5 u |
| Change 1 |
- 1 u - 30 |
+ 1 u + 30 |
| After 1 |
4 u + 120 |
6 u + 30 |
| Change 2 |
+ 3 u + 15 |
- 3 u - 15 |
| After 2 |
7 u + 135 |
3 u + 15 |
20% =
20100 =
1520% x 150
=
20100 x 150
= 30
50% x 30
=
50100 x 30
= 15
50% x 6 u
=
50100 x 6 u
= 3 u
Ivan had 360 less coins than Ahmad in the end. If another 360 coins are given to Ivan, both will have the same number of coins.
7 u + 135 = 3 u + 15 + 360
7 u - 3 u = 15 + 360 - 135
4 u = 240
1 u = 240 ÷ 4 = 20
Number of Ivan's coins at first
= 5 u
= 5 x 20
= 100
Answer: 100
