25% of the people are performers for a concert and the rest are spectators. 60% of the spectators are adults and there are 150 less child spectators than adult spectators. How many adult spectators must join so that 56% of the people are adult spectators?
|
Performers |
Spectators |
|
1x5 |
3x5 |
|
|
Children |
Adults |
|
|
2x3 |
3x3 |
Before |
5 u |
6 u |
9 u |
Change |
|
|
+ ? |
After |
11x1 = 11 u |
14x1 = 14 u |
25% =
25100 =
14 60% =
60100 =
35 56% =
56100 =
1425The total number of spectators at first is repeated. Make the total number of spectators the same. LCM of 3 and 5 is 15.
Number of less child spectators than adult spectators at first
= 9 u - 6 u
= 3 u
3 u = 150
1 u = 150 ÷ 3 = 50
If some adult spectators join, the total number of child spectators and performers remains unchanged.
Number of adult spectators who must join so that 56% of the people are adult spectators
= 14 u - 9 u
= 5 u
= 5 x 50
= 250
Answer(s): 250