20% of the people are performers for a concert and the rest are spectators. 70% of the spectators are parents and there are 1440 less child spectators than parent spectators. How many parent spectators must join so that 78% of the people are parent spectators?
|
Performers |
Spectators |
|
1x5 |
4x5 |
|
|
Children |
Parents |
|
|
3x2 |
7x2 |
Before |
5 u |
6 u |
14 u |
Change |
|
|
+ ? |
After |
11x1 = 11 u |
39x1 = 39 u |
20% =
20100 =
15 70% =
70100 =
710 78% =
78100 =
3950The total number of spectators at first is repeated. Make the total number of spectators the same. LCM of 4 and 10 is 20.
Number of less child spectators than parent spectators at first
= 14 u - 6 u
= 8 u
8 u = 1440
1 u = 1440 ÷ 8 = 180
If some parent spectators join, the total number of child spectators and performers remains unchanged.
Number of parent spectators who must join so that 78% of the people are parent spectators
= 39 u - 14 u
= 25 u
= 25 x 180
= 4500
Answer(s): 4500