Abi had 90% as many sweets as Jane. Abi gave away 20% of her sweets and Jane bought another 120 sweets. As a result, Abi now has 60% as many sweets as Jane. Find the number of sweets that Abi had in the end.
| |
Abi |
Jane |
| Before |
9x3 |
10x3 |
| Change |
- 1.8x3 |
+ 120 |
| After |
7.2x3 |
10x3 + 120 |
Comparing Abi and
Jane in the end |
3x7.2 |
5x7.2 |
| |
Abi |
Jane |
| Before |
27 u |
30 u |
| Change |
- 5.4 u |
+ 120 |
After
|
21.6 u
|
30 u + 120 =
36 u |
90% =
90100 =
91020% x 9
=
20100 x 9
= 1.8
60% =
60100 =
35The number of sweets that Abi had in the end is repeated.
Make the number of sweets that Abi had in the end the same.
The number of sweets that Jane had in the end is repeated.
30 u + 120 = 36 u
36 u - 30 u = 120
6 u = 120
1 u = 120 ÷ 6 = 20
Number of sweets that Abi had in the end
= 21.6 u
= 21.6 x 20
= 432
Answer: 432
