Liam has 70% as many beads as Neave. If Liam gives away 25% of the beads and Neave gives away 80% of his beads, they will have 232 beads altogether. How many beads do the two of them have?
| |
Liam |
Neave |
Total |
Comparing Liam
and Neave at first |
7x4 =
28 u |
10x4 =
40 u |
|
| Before |
4x7 =
28 u |
5x8 =
40 u |
|
| Change |
- 1x7 =
- 7 u |
- 4x8 =
- 32 u |
|
| After |
3x7 =
21 u |
1x8 =
8 u |
232 |
70% =
70100 =
710 25% =
25100 =
14 80% =
80100 =
45 The number of beads that Liam has at first is repeated. Make the number of beads that Liam has the same. LCM of 7 and 4 is 28 u.
The number of beads that Neave has at first is repeated. Make the number of beads that Neave has the same. LCM of 10 and 5 is 40 u.
Number of beads in the end
= 21 u + 8 u
= 29 u
29 u = 232
1 u = 232 ÷ 29 = 8
Total number of beads that the two of them have
= 28 u + 40 u
= 68 u
= 68 x 8
= 544
Answer(s): 544
