Elijah has 10% as many cards as Vaidev. If Elijah gives away 25% of the cards and Vaidev gives away 60% of his cards, they will have 152 cards altogether. How many cards do the two of them have?
| |
Elijah |
Vaidev |
Total |
Comparing Elijah
and Vaidev at first |
1x4 =
4 u |
10x4 =
40 u |
|
| Before |
4x1 =
4 u |
5x8 =
40 u |
|
| Change |
- 1x1 =
- 1 u |
- 3x8 =
- 24 u |
|
| After |
3x1 =
3 u |
2x8 =
16 u |
152 |
10% =
10100 =
110 25% =
25100 =
14 60% =
60100 =
35 The number of cards that Elijah has at first is repeated. Make the number of cards that Elijah has the same. LCM of 1 and 4 is 4 u.
The number of cards that Vaidev has at first is repeated. Make the number of cards that Vaidev has the same. LCM of 10 and 5 is 40 u.
Number of cards in the end
= 3 u + 16 u
= 19 u
19 u = 152
1 u = 152 ÷ 19 = 8
Total number of cards that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 8
= 352
Answer(s): 352
