George has 10% as many beads as Gabriel. If George gives away 50% of the beads and Gabriel gives away 20% of his beads, they will have 68 beads altogether. How many beads do the two of them have?
| |
George |
Gabriel |
Total |
Comparing George
and Gabriel at first |
1x2 =
2 u |
10x2 =
20 u |
|
| Before |
2x1 =
2 u |
5x4 =
20 u |
|
| Change |
- 1x1 =
- 1 u |
- 1x4 =
- 4 u |
|
| After |
1x1 =
1 u |
4x4 =
16 u |
68 |
10% =
10100 =
110 50% =
50100 =
12 20% =
20100 =
15 The number of beads that George has at first is repeated. Make the number of beads that George has the same. LCM of 1 and 2 is 2 u.
The number of beads that Gabriel has at first is repeated. Make the number of beads that Gabriel has the same. LCM of 10 and 5 is 20 u.
Number of beads in the end
= 1 u + 16 u
= 17 u
17 u = 68
1 u = 68 ÷ 17 = 4
Total number of beads that the two of them have
= 2 u + 20 u
= 22 u
= 22 x 4
= 88
Answer(s): 88
