Oscar has 10% as many beads as Gabriel. If Oscar gives away 25% of the beads and Gabriel gives away 70% of his beads, they will have 45 beads altogether. How many beads do the two of them have?
| |
Oscar |
Gabriel |
Total |
Comparing Oscar
and Gabriel at first |
1x4 =
4 u |
10x4 =
40 u |
|
| Before |
4x1 =
4 u |
10x4 =
40 u |
|
| Change |
- 1x1 =
- 1 u |
- 7x4 =
- 28 u |
|
| After |
3x1 =
3 u |
3x4 =
12 u |
45 |
10% =
10100 =
110 25% =
25100 =
14 70% =
70100 =
710 The number of beads that Oscar has at first is repeated. Make the number of beads that Oscar has the same. LCM of 1 and 4 is 4 u.
The number of beads that Gabriel has at first is repeated. Make the number of beads that Gabriel has the same. LCM of 10 and 10 is 40 u.
Number of beads in the end
= 3 u + 12 u
= 15 u
15 u = 45
1 u = 45 ÷ 15 = 3
Total number of beads that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 3
= 132
Answer(s): 132
