Caden has 30% as many marbles as Riordan. If Caden gives away 20% of the marbles and Riordan gives away 50% of his marbles, they will have 148 marbles altogether. How many marbles do the two of them have?
|
Caden |
Riordan |
Total |
Comparing Caden and Riordan at first |
3x5 = 15 u |
10x5 = 50 u |
|
Before |
5x3 = 15 u |
2x25 = 50 u |
|
Change |
- 1x3 = - 3 u |
- 1x25 = - 25 u |
|
After |
4x3 = 12 u |
1x25 = 25 u |
148 |
30% =
30100 =
310 20% =
20100 =
15 50% =
50100 =
12 The number of marbles that Caden has at first is repeated. Make the number of marbles that Caden has the same. LCM of 3 and 5 is 15 u.
The number of marbles that Riordan has at first is repeated. Make the number of marbles that Riordan has the same. LCM of 10 and 2 is 50 u.
Number of marbles in the end
= 12 u + 25 u
= 37 u
37 u = 148
1 u = 148 ÷ 37 = 4
Total number of marbles that the two of them have
= 15 u + 50 u
= 65 u
= 65 x 4
= 260
Answer(s): 260