Zane has 10% as many coins as Sam. If Zane gives away 25% of the coins and Sam gives away 90% of his coins, they will have 49 coins altogether. How many coins do the two of them have?
| |
Zane |
Sam |
Total |
Comparing Zane
and Sam at first |
1x4 =
4 u |
10x4 =
40 u |
|
| Before |
4x1 =
4 u |
10x4 =
40 u |
|
| Change |
- 1x1 =
- 1 u |
- 9x4 =
- 36 u |
|
| After |
3x1 =
3 u |
1x4 =
4 u |
49 |
10% =
10100 =
110 25% =
25100 =
14 90% =
90100 =
910 The number of coins that Zane has at first is repeated. Make the number of coins that Zane has the same. LCM of 1 and 4 is 4 u.
The number of coins that Sam has at first is repeated. Make the number of coins that Sam has the same. LCM of 10 and 10 is 40 u.
Number of coins in the end
= 3 u + 4 u
= 7 u
7 u = 49
1 u = 49 ÷ 7 = 7
Total number of coins that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 7
= 308
Answer(s): 308
