Michael has 90% as many marbles as Justin. If Michael gives away 20% of the marbles and Justin gives away 60% of his marbles, they will have 504 marbles altogether. How many marbles do the two of them have?
|
Michael |
Justin |
Total |
Comparing Michael and Justin at first |
9x5 = 45 u |
10x5 = 50 u |
|
Before |
5x9 = 45 u |
5x10 = 50 u |
|
Change |
- 1x9 = - 9 u |
- 3x10 = - 30 u |
|
After |
4x9 = 36 u |
2x10 = 20 u |
504 |
90% =
90100 =
910 20% =
20100 =
15 60% =
60100 =
35 The number of marbles that Michael has at first is repeated. Make the number of marbles that Michael has the same. LCM of 9 and 5 is 45 u.
The number of marbles that Justin has at first is repeated. Make the number of marbles that Justin has the same. LCM of 10 and 5 is 50 u.
Number of marbles in the end
= 36 u + 20 u
= 56 u
56 u = 504
1 u = 504 ÷ 56 = 9
Total number of marbles that the two of them have
= 45 u + 50 u
= 95 u
= 95 x 9
= 855
Answer(s): 855