Jeremy has 70% as many beads as Peter. If Jeremy gives away 20% of the beads and Peter gives away 50% of his beads, they will have 583 beads altogether. How many beads do the two of them have?
| |
Jeremy |
Peter |
Total |
Comparing Jeremy
and Peter at first |
7x5 =
35 u |
10x5 =
50 u |
|
| Before |
5x7 =
35 u |
2x25 =
50 u |
|
| Change |
- 1x7 =
- 7 u |
- 1x25 =
- 25 u |
|
| After |
4x7 =
28 u |
1x25 =
25 u |
583 |
70% =
70100 =
710 20% =
20100 =
15 50% =
50100 =
12 The number of beads that Jeremy has at first is repeated. Make the number of beads that Jeremy has the same. LCM of 7 and 5 is 35 u.
The number of beads that Peter has at first is repeated. Make the number of beads that Peter has the same. LCM of 10 and 2 is 50 u.
Number of beads in the end
= 28 u + 25 u
= 53 u
53 u = 583
1 u = 583 ÷ 53 = 11
Total number of beads that the two of them have
= 35 u + 50 u
= 85 u
= 85 x 11
= 935
Answer(s): 935
