Neave has 30% as many coins as Ben. If Neave gives away 50% of the coins and Ben gives away 20% of his coins, they will have 133 coins altogether. How many coins do the two of them have?
| |
Neave |
Ben |
Total |
Comparing Neave
and Ben at first |
3x2 =
6 u |
10x2 =
20 u |
|
| Before |
2x3 =
6 u |
5x4 =
20 u |
|
| Change |
- 1x3 =
- 3 u |
- 1x4 =
- 4 u |
|
| After |
1x3 =
3 u |
4x4 =
16 u |
133 |
30% =
30100 =
310 50% =
50100 =
12 20% =
20100 =
15 The number of coins that Neave has at first is repeated. Make the number of coins that Neave has the same. LCM of 3 and 2 is 6 u.
The number of coins that Ben has at first is repeated. Make the number of coins that Ben has the same. LCM of 10 and 5 is 20 u.
Number of coins in the end
= 3 u + 16 u
= 19 u
19 u = 133
1 u = 133 ÷ 19 = 7
Total number of coins that the two of them have
= 6 u + 20 u
= 26 u
= 26 x 7
= 182
Answer(s): 182
