Caden has 10% as many marbles as Luis. If Caden gives away 25% of the marbles and Luis gives away 80% of his marbles, they will have 55 marbles altogether. How many marbles do the two of them have?
|
Caden |
Luis |
Total |
Comparing Caden and Luis at first |
1x4 = 4 u |
10x4 = 40 u |
|
Before |
4x1 = 4 u |
5x8 = 40 u |
|
Change |
- 1x1 = - 1 u |
- 4x8 = - 32 u |
|
After |
3x1 = 3 u |
1x8 = 8 u |
55 |
10% =
10100 =
110 25% =
25100 =
14 80% =
80100 =
45 The number of marbles that Caden has at first is repeated. Make the number of marbles that Caden has the same. LCM of 1 and 4 is 4 u.
The number of marbles that Luis has at first is repeated. Make the number of marbles that Luis has the same. LCM of 10 and 5 is 40 u.
Number of marbles in the end
= 3 u + 8 u
= 11 u
11 u = 55
1 u = 55 ÷ 11 = 5
Total number of marbles that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 5
= 220
Answer(s): 220