Charlie has 70% as many coins as Dylan. If Charlie gives away 25% of the coins and Dylan gives away 60% of his coins, they will have 444 coins altogether. How many coins do the two of them have?
| |
Charlie |
Dylan |
Total |
Comparing Charlie
and Dylan at first |
7x4 =
28 u |
10x4 =
40 u |
|
| Before |
4x7 =
28 u |
5x8 =
40 u |
|
| Change |
- 1x7 =
- 7 u |
- 3x8 =
- 24 u |
|
| After |
3x7 =
21 u |
2x8 =
16 u |
444 |
70% =
70100 =
710 25% =
25100 =
14 60% =
60100 =
35 The number of coins that Charlie has at first is repeated. Make the number of coins that Charlie has the same. LCM of 7 and 4 is 28 u.
The number of coins that Dylan has at first is repeated. Make the number of coins that Dylan has the same. LCM of 10 and 5 is 40 u.
Number of coins in the end
= 21 u + 16 u
= 37 u
37 u = 444
1 u = 444 ÷ 37 = 12
Total number of coins that the two of them have
= 28 u + 40 u
= 68 u
= 68 x 12
= 816
Answer(s): 816
