Fred has 70% as many beads as Zane. If Fred gives away 20% of the beads and Zane gives away 40% of his beads, they will have 696 beads altogether. How many beads do the two of them have?
| |
Fred |
Zane |
Total |
Comparing Fred
and Zane at first |
7x5 =
35 u |
10x5 =
50 u |
|
| Before |
5x7 =
35 u |
5x10 =
50 u |
|
| Change |
- 1x7 =
- 7 u |
- 2x10 =
- 20 u |
|
| After |
4x7 =
28 u |
3x10 =
30 u |
696 |
70% =
70100 =
710 20% =
20100 =
15 40% =
40100 =
25 The number of beads that Fred has at first is repeated. Make the number of beads that Fred has the same. LCM of 7 and 5 is 35 u.
The number of beads that Zane has at first is repeated. Make the number of beads that Zane has the same. LCM of 10 and 5 is 50 u.
Number of beads in the end
= 28 u + 30 u
= 58 u
58 u = 696
1 u = 696 ÷ 58 = 12
Total number of beads that the two of them have
= 35 u + 50 u
= 85 u
= 85 x 12
= 1020
Answer(s): 1020
