Liam has 30% as many pens as Jenson. If Liam gives away 25% of the pens and Jenson gives away 40% of his pens, they will have 264 pens altogether. How many pens do the two of them have?
| |
Liam |
Jenson |
Total |
Comparing Liam
and Jenson at first |
3x4 =
12 u |
10x4 =
40 u |
|
| Before |
4x3 =
12 u |
5x8 =
40 u |
|
| Change |
- 1x3 =
- 3 u |
- 2x8 =
- 16 u |
|
| After |
3x3 =
9 u |
3x8 =
24 u |
264 |
30% =
30100 =
310 25% =
25100 =
14 40% =
40100 =
25 The number of pens that Liam has at first is repeated. Make the number of pens that Liam has the same. LCM of 3 and 4 is 12 u.
The number of pens that Jenson has at first is repeated. Make the number of pens that Jenson has the same. LCM of 10 and 5 is 40 u.
Number of pens in the end
= 9 u + 24 u
= 33 u
33 u = 264
1 u = 264 ÷ 33 = 8
Total number of pens that the two of them have
= 12 u + 40 u
= 52 u
= 52 x 8
= 416
Answer(s): 416
