Bryan has 10% as many coins as Lee. If Bryan gives away 25% of the coins and Lee gives away 40% of his coins, they will have 297 coins altogether. How many coins do the two of them have?
| |
Bryan |
Lee |
Total |
Comparing Bryan
and Lee at first |
1x4 =
4 u |
10x4 =
40 u |
|
| Before |
4x1 =
4 u |
5x8 =
40 u |
|
| Change |
- 1x1 =
- 1 u |
- 2x8 =
- 16 u |
|
| After |
3x1 =
3 u |
3x8 =
24 u |
297 |
10% =
10100 =
110 25% =
25100 =
14 40% =
40100 =
25 The number of coins that Bryan has at first is repeated. Make the number of coins that Bryan has the same. LCM of 1 and 4 is 4 u.
The number of coins that Lee has at first is repeated. Make the number of coins that Lee has the same. LCM of 10 and 5 is 40 u.
Number of coins in the end
= 3 u + 24 u
= 27 u
27 u = 297
1 u = 297 ÷ 27 = 11
Total number of coins that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 11
= 484
Answer(s): 484
