Rael has 10% as many beads as Julian. If Rael gives away 25% of the beads and Julian gives away 60% of his beads, they will have 95 beads altogether. How many beads do the two of them have?
|
Rael |
Julian |
Total |
Comparing Rael and Julian at first |
1x4 = 4 u |
10x4 = 40 u |
|
Before |
4x1 = 4 u |
5x8 = 40 u |
|
Change |
- 1x1 = - 1 u |
- 3x8 = - 24 u |
|
After |
3x1 = 3 u |
2x8 = 16 u |
95 |
10% =
10100 =
110 25% =
25100 =
14 60% =
60100 =
35 The number of beads that Rael has at first is repeated. Make the number of beads that Rael has the same. LCM of 1 and 4 is 4 u.
The number of beads that Julian has at first is repeated. Make the number of beads that Julian has the same. LCM of 10 and 5 is 40 u.
Number of beads in the end
= 3 u + 16 u
= 19 u
19 u = 95
1 u = 95 ÷ 19 = 5
Total number of beads that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 5
= 220
Answer(s): 220