Daniel has 10% as many buttons as Zane. If Daniel gives away 25% of the buttons and Zane gives away 80% of his buttons, they will have 132 buttons altogether. How many buttons do the two of them have?
|
Daniel |
Zane |
Total |
Comparing Daniel and Zane at first |
1x4 = 4 u |
10x4 = 40 u |
|
Before |
4x1 = 4 u |
5x8 = 40 u |
|
Change |
- 1x1 = - 1 u |
- 4x8 = - 32 u |
|
After |
3x1 = 3 u |
1x8 = 8 u |
132 |
10% =
10100 =
110 25% =
25100 =
14 80% =
80100 =
45 The number of buttons that Daniel has at first is repeated. Make the number of buttons that Daniel has the same. LCM of 1 and 4 is 4 u.
The number of buttons that Zane has at first is repeated. Make the number of buttons that Zane has the same. LCM of 10 and 5 is 40 u.
Number of buttons in the end
= 3 u + 8 u
= 11 u
11 u = 132
1 u = 132 ÷ 11 = 12
Total number of buttons that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 12
= 528
Answer(s): 528