Warren has 90% as many coins as Asher. If Warren gives away 25% of the coins and Asher gives away 80% of his coins, they will have 280 coins altogether. How many coins do the two of them have?
| |
Warren |
Asher |
Total |
Comparing Warren
and Asher at first |
9x4 =
36 u |
10x4 =
40 u |
|
| Before |
4x9 =
36 u |
5x8 =
40 u |
|
| Change |
- 1x9 =
- 9 u |
- 4x8 =
- 32 u |
|
| After |
3x9 =
27 u |
1x8 =
8 u |
280 |
90% =
90100 =
910 25% =
25100 =
14 80% =
80100 =
45 The number of coins that Warren has at first is repeated. Make the number of coins that Warren has the same. LCM of 9 and 4 is 36 u.
The number of coins that Asher has at first is repeated. Make the number of coins that Asher has the same. LCM of 10 and 5 is 40 u.
Number of coins in the end
= 27 u + 8 u
= 35 u
35 u = 280
1 u = 280 ÷ 35 = 8
Total number of coins that the two of them have
= 36 u + 40 u
= 76 u
= 76 x 8
= 608
Answer(s): 608
