Valen has 10% as many erasers as Riordan. If Valen gives away 50% of the erasers and Riordan gives away 80% of his erasers, they will have 50 erasers altogether. How many erasers do the two of them have?
|
Valen |
Riordan |
Total |
Comparing Valen and Riordan at first |
1x2 = 2 u |
10x2 = 20 u |
|
Before |
2x1 = 2 u |
5x4 = 20 u |
|
Change |
- 1x1 = - 1 u |
- 4x4 = - 16 u |
|
After |
1x1 = 1 u |
1x4 = 4 u |
50 |
10% =
10100 =
110 50% =
50100 =
12 80% =
80100 =
45 The number of erasers that Valen has at first is repeated. Make the number of erasers that Valen has the same. LCM of 1 and 2 is 2 u.
The number of erasers that Riordan has at first is repeated. Make the number of erasers that Riordan has the same. LCM of 10 and 5 is 20 u.
Number of erasers in the end
= 1 u + 4 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of erasers that the two of them have
= 2 u + 20 u
= 22 u
= 22 x 10
= 220
Answer(s): 220