Vincent has 10% as many beads as Elijah. If Vincent gives away 50% of the beads and Elijah gives away 60% of his beads, they will have 63 beads altogether. How many beads do the two of them have?
| |
Vincent |
Elijah |
Total |
Comparing Vincent
and Elijah at first |
1x2 =
2 u |
10x2 =
20 u |
|
| Before |
2x1 =
2 u |
5x4 =
20 u |
|
| Change |
- 1x1 =
- 1 u |
- 3x4 =
- 12 u |
|
| After |
1x1 =
1 u |
2x4 =
8 u |
63 |
10% =
10100 =
110 50% =
50100 =
12 60% =
60100 =
35 The number of beads that Vincent has at first is repeated. Make the number of beads that Vincent has the same. LCM of 1 and 2 is 2 u.
The number of beads that Elijah has at first is repeated. Make the number of beads that Elijah has the same. LCM of 10 and 5 is 20 u.
Number of beads in the end
= 1 u + 8 u
= 9 u
9 u = 63
1 u = 63 ÷ 9 = 7
Total number of beads that the two of them have
= 2 u + 20 u
= 22 u
= 22 x 7
= 154
Answer(s): 154
