Jenson has 90% as many coins as Carl. If Jenson gives away 25% of the coins and Carl gives away 50% of his coins, they will have 141 coins altogether. How many coins do the two of them have?
| |
Jenson |
Carl |
Total |
Comparing Jenson
and Carl at first |
9x4 =
36 u |
10x4 =
40 u |
|
| Before |
4x9 =
36 u |
2x20 =
40 u |
|
| Change |
- 1x9 =
- 9 u |
- 1x20 =
- 20 u |
|
| After |
3x9 =
27 u |
1x20 =
20 u |
141 |
90% =
90100 =
910 25% =
25100 =
14 50% =
50100 =
12 The number of coins that Jenson has at first is repeated. Make the number of coins that Jenson has the same. LCM of 9 and 4 is 36 u.
The number of coins that Carl has at first is repeated. Make the number of coins that Carl has the same. LCM of 10 and 2 is 40 u.
Number of coins in the end
= 27 u + 20 u
= 47 u
47 u = 141
1 u = 141 ÷ 47 = 3
Total number of coins that the two of them have
= 36 u + 40 u
= 76 u
= 76 x 3
= 228
Answer(s): 228
