Elijah had 50% more balls than Cody. Elijah gave 30% of his balls to Cody. Cody in return gave 40% of his balls to Elijah. In the end, Cody had 152 less balls than Elijah. How many balls did Cody have in the end?
|
Elijah |
Cody |
Before |
150% |
100% |
Change 1 |
- 45% |
+ 45% |
After 1 |
105% |
145% |
Change 2 |
+ 58% |
- 58% |
After 2 |
163% |
87% |
Number of balls that Elijah had at first in percent
= 100% + 50%
= 150%
Number of balls that Elijah gave to Cody in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of balls that Cody gave to Elijah in percent
= 40% x 145%
=
40100 x 145%
= 58%
Number of less balls that Cody had than Elijah in the end
= 163% - 87%
= 76%
76% → 152
1% → 152 ÷ 76 = 2
Number of balls that Cody had in the end
= 87%
= 87 x 2
= 300
Answer(s): 300