Daniel had 50% more balls than Zane. Daniel gave 20% of his balls to Zane. Zane in return gave 30% of his balls to Daniel. In the end, Zane had 340 less balls than Daniel. How many balls did Zane have in the end?
| |
Daniel |
Zane |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 39% |
- 39% |
| After 2 |
159% |
91% |
Number of balls that Daniel had at first in percent
= 100% + 50%
= 150%
Number of balls that Daniel gave to Zane in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Zane gave to Daniel in percent
= 30% x 130%
=
30100 x 130%
= 39%
Number of less balls that Zane had than Daniel in the end
= 159% - 91%
= 68%
68% → 340
1% → 340 ÷ 68 = 5
Number of balls that Zane had in the end
= 91%
= 91 x 5
= 750
Answer(s): 750
