Lee had 40% more marbles than Neave. Lee gave 30% of his marbles to Neave. Neave in return gave 50% of his marbles to Lee. In the end, Neave had 294 less marbles than Lee. How many marbles did Neave have in the end?
| |
Lee |
Neave |
| Before |
140% |
100% |
| Change 1 |
- 42% |
+ 42% |
| After 1 |
98% |
142% |
| Change 2 |
+ 71% |
- 71% |
| After 2 |
169% |
71% |
Number of marbles that Lee had at first in percent
= 100% + 40%
= 140%
Number of marbles that Lee gave to Neave in percent
= 30% x 140%
=
30100 x 140%
= 42%
Number of marbles that Neave gave to Lee in percent
= 50% x 142%
=
50100 x 142%
= 71%
Number of less marbles that Neave had than Lee in the end
= 169% - 71%
= 98%
98% → 294
1% → 294 ÷ 98 = 3
Number of marbles that Neave had in the end
= 71%
= 71 x 3
= 420
Answer(s): 420
