Bryan had 50% more balls than David. Bryan gave 20% of his balls to David. David in return gave 20% of his balls to Bryan. In the end, David had 504 less balls than Bryan. How many balls did Bryan have at first?
| |
Bryan |
David |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 26% |
- 26% |
| After 2 |
146% |
104% |
Number of balls that Bryan had at first in percent
= 100% + 50%
= 150%
Number of balls that Bryan gave to David in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that David gave to Bryan in percent
= 20% x 130%
=
20100 x 130%
= 26%
Number of less balls that David had than Bryan in the end
= 146% - 104%
= 42%
42% → 504
1% → 504 ÷ 42 = 12
Number of balls that Bryan had at first
= 150%
= 150 x 12
= 1800
Answer(s): 1800
