Sam had 20% more marbles than Brandon. Sam gave 20% of his marbles to Brandon. Brandon in return gave 25% of his marbles to Sam. In the end, Brandon had 238 less marbles than Sam. How many marbles did Brandon have in the end?
| |
Sam |
Brandon |
| Before |
120% |
100% |
| Change 1 |
- 24% |
+ 24% |
| After 1 |
96% |
124% |
| Change 2 |
+ 31% |
- 31% |
| After 2 |
127% |
93% |
Number of marbles that Sam had at first in percent
= 100% + 20%
= 120%
Number of marbles that Sam gave to Brandon in percent
= 20% x 120%
=
20100 x 120%
= 24%
Number of marbles that Brandon gave to Sam in percent
= 25% x 124%
=
25100 x 124%
= 31%
Number of less marbles that Brandon had than Sam in the end
= 127% - 93%
= 34%
34% → 238
1% → 238 ÷ 34 = 7
Number of marbles that Brandon had in the end
= 93%
= 93 x 7
= 840
Answer(s): 840
