Michael had 50% more balls than Bobby. Michael gave 20% of his balls to Bobby. Bobby in return gave 30% of his balls to Michael. In the end, Bobby had 544 less balls than Michael. How many balls did Bobby have in the end?
| |
Michael |
Bobby |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 39% |
- 39% |
| After 2 |
159% |
91% |
Number of balls that Michael had at first in percent
= 100% + 50%
= 150%
Number of balls that Michael gave to Bobby in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Bobby gave to Michael in percent
= 30% x 130%
=
30100 x 130%
= 39%
Number of less balls that Bobby had than Michael in the end
= 159% - 91%
= 68%
68% → 544
1% → 544 ÷ 68 = 8
Number of balls that Bobby had in the end
= 91%
= 91 x 8
= 1200
Answer(s): 1200
