Nick had 20% more beads than Simon. Nick gave 25% of his beads to Simon. Simon in return gave 20% of his beads to Nick. In the end, Simon had 48 less beads than Nick. How many beads did Nick have at first?
| |
Nick |
Simon |
| Before |
120% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
90% |
130% |
| Change 2 |
+ 26% |
- 26% |
| After 2 |
116% |
104% |
Number of beads that Nick had at first in percent
= 100% + 20%
= 120%
Number of beads that Nick gave to Simon in percent
= 25% x 120%
=
25100 x 120%
= 30%
Number of beads that Simon gave to Nick in percent
= 20% x 130%
=
20100 x 130%
= 26%
Number of less beads that Simon had than Nick in the end
= 116% - 104%
= 12%
12% → 48
1% → 48 ÷ 12 = 4
Number of beads that Nick had at first
= 120%
= 120 x 4
= 480
Answer(s): 480
