Pierre had 50% more balls than Xavier. Pierre gave 20% of his balls to Xavier. Xavier in return gave 50% of his balls to Pierre. In the end, Xavier had 240 less balls than Pierre. How many balls did Xavier have in the end?
| |
Pierre |
Xavier |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 65% |
- 65% |
| After 2 |
185% |
65% |
Number of balls that Pierre had at first in percent
= 100% + 50%
= 150%
Number of balls that Pierre gave to Xavier in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Xavier gave to Pierre in percent
= 50% x 130%
=
50100 x 130%
= 65%
Number of less balls that Xavier had than Pierre in the end
= 185% - 65%
= 120%
120% → 240
1% → 240 ÷ 120 = 2
Number of balls that Xavier had in the end
= 65%
= 65 x 2
= 300
Answer(s): 300
