Luis had 40% more balls than Zeph. Luis gave 25% of his balls to Zeph. Zeph in return gave 20% of his balls to Luis. In the end, Zeph had 216 less balls than Luis. How many balls did Luis have at first?
| |
Luis |
Zeph |
| Before |
140% |
100% |
| Change 1 |
- 35% |
+ 35% |
| After 1 |
105% |
135% |
| Change 2 |
+ 27% |
- 27% |
| After 2 |
132% |
108% |
Number of balls that Luis had at first in percent
= 100% + 40%
= 140%
Number of balls that Luis gave to Zeph in percent
= 25% x 140%
=
25100 x 140%
= 35%
Number of balls that Zeph gave to Luis in percent
= 20% x 135%
=
20100 x 135%
= 27%
Number of less balls that Zeph had than Luis in the end
= 132% - 108%
= 24%
24% → 216
1% → 216 ÷ 24 = 9
Number of balls that Luis had at first
= 140%
= 140 x 9
= 1260
Answer(s): 1260
