Sean had 50% more balls than Luke. Sean gave 20% of his balls to Luke. Luke in return gave 20% of his balls to Sean. In the end, Luke had 336 less balls than Sean. How many balls did Sean have at first?
| |
Sean |
Luke |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 26% |
- 26% |
| After 2 |
146% |
104% |
Number of balls that Sean had at first in percent
= 100% + 50%
= 150%
Number of balls that Sean gave to Luke in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Luke gave to Sean in percent
= 20% x 130%
=
20100 x 130%
= 26%
Number of less balls that Luke had than Sean in the end
= 146% - 104%
= 42%
42% → 336
1% → 336 ÷ 42 = 8
Number of balls that Sean had at first
= 150%
= 150 x 8
= 1200
Answer(s): 1200
