Eric had 50% more balls than Archie. Eric gave 10% of his balls to Archie. Archie in return gave 20% of his balls to Eric. In the end, Archie had 198 less balls than Eric. How many balls did Archie have in the end?
| |
Eric |
Archie |
| Before |
150% |
100% |
| Change 1 |
- 15% |
+ 15% |
| After 1 |
135% |
115% |
| Change 2 |
+ 23% |
- 23% |
| After 2 |
158% |
92% |
Number of balls that Eric had at first in percent
= 100% + 50%
= 150%
Number of balls that Eric gave to Archie in percent
= 10% x 150%
=
10100 x 150%
= 15%
Number of balls that Archie gave to Eric in percent
= 20% x 115%
=
20100 x 115%
= 23%
Number of less balls that Archie had than Eric in the end
= 158% - 92%
= 66%
66% → 198
1% → 198 ÷ 66 = 3
Number of balls that Archie had in the end
= 92%
= 92 x 3
= 450
Answer(s): 450
