Lee had 20% more beads than Charlie. Lee gave 20% of his beads to Charlie. Charlie in return gave 25% of his beads to Lee. In the end, Charlie had 408 less beads than Lee. How many beads did Lee have at first?
| |
Lee |
Charlie |
| Before |
120% |
100% |
| Change 1 |
- 24% |
+ 24% |
| After 1 |
96% |
124% |
| Change 2 |
+ 31% |
- 31% |
| After 2 |
127% |
93% |
Number of beads that Lee had at first in percent
= 100% + 20%
= 120%
Number of beads that Lee gave to Charlie in percent
= 20% x 120%
=
20100 x 120%
= 24%
Number of beads that Charlie gave to Lee in percent
= 25% x 124%
=
25100 x 124%
= 31%
Number of less beads that Charlie had than Lee in the end
= 127% - 93%
= 34%
34% → 408
1% → 408 ÷ 34 = 12
Number of beads that Lee had at first
= 120%
= 120 x 12
= 1440
Answer(s): 1440
