Paul had 50% more beads than Liam. Paul gave 30% of his beads to Liam. Liam in return gave 20% of his beads to Paul. In the end, Liam had 36 less beads than Paul. How many beads did Paul have at first?
| |
Paul |
Liam |
| Before |
150% |
100% |
| Change 1 |
- 45% |
+ 45% |
| After 1 |
105% |
145% |
| Change 2 |
+ 29% |
- 29% |
| After 2 |
134% |
116% |
Number of beads that Paul had at first in percent
= 100% + 50%
= 150%
Number of beads that Paul gave to Liam in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of beads that Liam gave to Paul in percent
= 20% x 145%
=
20100 x 145%
= 29%
Number of less beads that Liam had than Paul in the end
= 134% - 116%
= 18%
18% → 36
1% → 36 ÷ 18 = 2
Number of beads that Paul had at first
= 150%
= 150 x 2
= 300
Answer(s): 300
