Simon had 50% more balls than Ahmad. Simon gave 20% of his balls to Ahmad. Ahmad in return gave 40% of his balls to Simon. In the end, Ahmad had 188 less balls than Simon. How many balls did Ahmad have in the end?
| |
Simon |
Ahmad |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 52% |
- 52% |
| After 2 |
172% |
78% |
Number of balls that Simon had at first in percent
= 100% + 50%
= 150%
Number of balls that Simon gave to Ahmad in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Ahmad gave to Simon in percent
= 40% x 130%
=
40100 x 130%
= 52%
Number of less balls that Ahmad had than Simon in the end
= 172% - 78%
= 94%
94% → 188
1% → 188 ÷ 94 = 2
Number of balls that Ahmad had in the end
= 78%
= 78 x 2
= 300
Answer(s): 300
