Xavier had 20% more balls than Sam. Xavier gave 25% of his balls to Sam. Sam in return gave 40% of his balls to Xavier. In the end, Sam had 192 less balls than Xavier. How many balls did Xavier have at first?
| |
Xavier |
Sam |
| Before |
120% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
90% |
130% |
| Change 2 |
+ 52% |
- 52% |
| After 2 |
142% |
78% |
Number of balls that Xavier had at first in percent
= 100% + 20%
= 120%
Number of balls that Xavier gave to Sam in percent
= 25% x 120%
=
25100 x 120%
= 30%
Number of balls that Sam gave to Xavier in percent
= 40% x 130%
=
40100 x 130%
= 52%
Number of less balls that Sam had than Xavier in the end
= 142% - 78%
= 64%
64% → 192
1% → 192 ÷ 64 = 3
Number of balls that Xavier had at first
= 120%
= 120 x 3
= 360
Answer(s): 360
