Carl had 40% more balls than Zane. Carl gave 25% of his balls to Zane. Zane in return gave 20% of his balls to Carl. In the end, Zane had 192 less balls than Carl. How many balls did Zane have in the end?
| |
Carl |
Zane |
| Before |
140% |
100% |
| Change 1 |
- 35% |
+ 35% |
| After 1 |
105% |
135% |
| Change 2 |
+ 27% |
- 27% |
| After 2 |
132% |
108% |
Number of balls that Carl had at first in percent
= 100% + 40%
= 140%
Number of balls that Carl gave to Zane in percent
= 25% x 140%
=
25100 x 140%
= 35%
Number of balls that Zane gave to Carl in percent
= 20% x 135%
=
20100 x 135%
= 27%
Number of less balls that Zane had than Carl in the end
= 132% - 108%
= 24%
24% → 192
1% → 192 ÷ 24 = 8
Number of balls that Zane had in the end
= 108%
= 108 x 8
= 1120
Answer(s): 1120
