Albert had 50% more balls than Ken. Albert gave 30% of his balls to Ken. Ken in return gave 20% of his balls to Albert. In the end, Ken had 180 less balls than Albert. How many balls did Albert have at first?
| |
Albert |
Ken |
| Before |
150% |
100% |
| Change 1 |
- 45% |
+ 45% |
| After 1 |
105% |
145% |
| Change 2 |
+ 29% |
- 29% |
| After 2 |
134% |
116% |
Number of balls that Albert had at first in percent
= 100% + 50%
= 150%
Number of balls that Albert gave to Ken in percent
= 30% x 150%
=
30100 x 150%
= 45%
Number of balls that Ken gave to Albert in percent
= 20% x 145%
=
20100 x 145%
= 29%
Number of less balls that Ken had than Albert in the end
= 134% - 116%
= 18%
18% → 180
1% → 180 ÷ 18 = 10
Number of balls that Albert had at first
= 150%
= 150 x 10
= 1500
Answer(s): 1500
