Howard had 40% more marbles than Billy. Howard gave 20% of his marbles to Billy. Billy in return gave 25% of his marbles to Howard. In the end, Billy had 432 less marbles than Howard. How many marbles did Billy have in the end?
| |
Howard |
Billy |
| Before |
140% |
100% |
| Change 1 |
- 28% |
+ 28% |
| After 1 |
112% |
128% |
| Change 2 |
+ 32% |
- 32% |
| After 2 |
144% |
96% |
Number of marbles that Howard had at first in percent
= 100% + 40%
= 140%
Number of marbles that Howard gave to Billy in percent
= 20% x 140%
=
20100 x 140%
= 28%
Number of marbles that Billy gave to Howard in percent
= 25% x 128%
=
25100 x 128%
= 32%
Number of less marbles that Billy had than Howard in the end
= 144% - 96%
= 48%
48% → 432
1% → 432 ÷ 48 = 9
Number of marbles that Billy had in the end
= 96%
= 96 x 9
= 1260
Answer(s): 1260
