Warren had 50% more balls than Bryan. Warren gave 20% of his balls to Bryan. Bryan in return gave 10% of his balls to Warren. In the end, Bryan had 48 less balls than Warren. How many balls did Bryan have in the end?
| |
Warren |
Bryan |
| Before |
150% |
100% |
| Change 1 |
- 30% |
+ 30% |
| After 1 |
120% |
130% |
| Change 2 |
+ 13% |
- 13% |
| After 2 |
133% |
117% |
Number of balls that Warren had at first in percent
= 100% + 50%
= 150%
Number of balls that Warren gave to Bryan in percent
= 20% x 150%
=
20100 x 150%
= 30%
Number of balls that Bryan gave to Warren in percent
= 10% x 130%
=
10100 x 130%
= 13%
Number of less balls that Bryan had than Warren in the end
= 133% - 117%
= 16%
16% → 48
1% → 48 ÷ 16 = 3
Number of balls that Bryan had in the end
= 117%
= 117 x 3
= 450
Answer(s): 450
